2x^2+4y^2=16

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Solution for 2x^2+4y^2=16 equation:


Simplifying
2x2 + 4y2 = 16

Solving
2x2 + 4y2 = 16

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4y2' to each side of the equation.
2x2 + 4y2 + -4y2 = 16 + -4y2

Combine like terms: 4y2 + -4y2 = 0
2x2 + 0 = 16 + -4y2
2x2 = 16 + -4y2

Divide each side by '2'.
x2 = 8 + -2y2

Simplifying
x2 = 8 + -2y2

Reorder the terms:
-8 + x2 + 2y2 = 8 + -2y2 + -8 + 2y2

Reorder the terms:
-8 + x2 + 2y2 = 8 + -8 + -2y2 + 2y2

Combine like terms: 8 + -8 = 0
-8 + x2 + 2y2 = 0 + -2y2 + 2y2
-8 + x2 + 2y2 = -2y2 + 2y2

Combine like terms: -2y2 + 2y2 = 0
-8 + x2 + 2y2 = 0

The solution to this equation could not be determined.

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